32^x+4=(1/128)^-4x-15

Solution for 32^x+4=(1/128)^-4x-15 equation:

32^x+4=(1/128)^-4x-15

We move all terms to the left:

32^x+4-((1/128)^-4x-15)=0


Domain of the equation: 128)^-4x-15)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

32^x-((+1/128)^-4x-15)+4=0

We multiply all the terms by the denominator


32^x*128)^-4x-15)-((+4*128)^-4x-15)+1=0

We add all the numbers together, and all the variables

32^x*128)^-4x-15)-(512^-4x-15)+1=0

Wy multiply elements

4096x^2=0

a = 4096; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4096·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8192}=0$